blob: b1fefc5f20abfa84d08132a3330f5572667d6aea [file] [log] [blame]
; RUN: llvm-as < %s | opt -reassociate -dce -gcse | llvm-dis | grep add | wc -l | grep 8
; This test corresponds to GCC PR16157. Reassociate should arrange for 4 additions to be
; left in each function.
; We currently don't implement this. This would require looking globally to
; find out which expressions are available, which we currently do not do.
; XFAIL: *
%a4 = external global int
%a3 = external global int
%a2 = external global int
%a1 = external global int
%a0 = external global int
%b4 = external global int
%b3 = external global int
%b2 = external global int
%b1 = external global int
implementation ; Functions:
void %test1() {
%tmp.0 = load int* %a4 ; <int> [#uses=1]
%tmp.1 = load int* %a3 ; <int> [#uses=2]
%tmp.2 = add int %tmp.0, %tmp.1 ; <int> [#uses=1]
%tmp.3 = load int* %a2 ; <int> [#uses=3]
%tmp.4 = add int %tmp.2, %tmp.3 ; <int> [#uses=1]
%tmp.5 = load int* %a1 ; <int> [#uses=4]
%tmp.6 = add int %tmp.4, %tmp.5 ; <int> [#uses=1]
%tmp.7 = load int* %a0 ; <int> [#uses=4]
%tmp.8 = add int %tmp.6, %tmp.7 ; <int> [#uses=1]
store int %tmp.8, int* %a4
%tmp.11 = add int %tmp.1, %tmp.3 ; <int> [#uses=1]
%tmp.13 = add int %tmp.11, %tmp.5 ; <int> [#uses=1]
%tmp.15 = add int %tmp.13, %tmp.7 ; <int> [#uses=1]
store int %tmp.15, int* %a3
%tmp.18 = add int %tmp.3, %tmp.5 ; <int> [#uses=1]
%tmp.20 = add int %tmp.18, %tmp.7 ; <int> [#uses=1]
store int %tmp.20, int* %a2
%tmp.23 = add int %tmp.5, %tmp.7 ; <int> [#uses=1]
store int %tmp.23, int* %a1
ret void
}
void %test2() {
%tmp.0 = load int* %a4 ; <int> [#uses=1]
%tmp.1 = load int* %a3 ; <int> [#uses=2]
%tmp.2 = add int %tmp.0, %tmp.1 ; <int> [#uses=1]
%tmp.3 = load int* %a2 ; <int> [#uses=3]
%tmp.4 = add int %tmp.2, %tmp.3 ; <int> [#uses=1]
%tmp.5 = load int* %a1 ; <int> [#uses=4]
%tmp.6 = add int %tmp.4, %tmp.5 ; <int> [#uses=1]
%tmp.7 = load int* %a0 ; <int> [#uses=4]
%tmp.8 = add int %tmp.6, %tmp.7 ; <int> [#uses=1]
store int %tmp.8, int* %b4
%tmp.11 = add int %tmp.1, %tmp.3 ; <int> [#uses=1]
%tmp.13 = add int %tmp.11, %tmp.5 ; <int> [#uses=1]
%tmp.15 = add int %tmp.13, %tmp.7 ; <int> [#uses=1]
store int %tmp.15, int* %b3
%tmp.18 = add int %tmp.3, %tmp.5 ; <int> [#uses=1]
%tmp.20 = add int %tmp.18, %tmp.7 ; <int> [#uses=1]
store int %tmp.20, int* %b2
%tmp.23 = add int %tmp.5, %tmp.7 ; <int> [#uses=1]
store int %tmp.23, int* %b1
ret void
}