Raman Tenneti | eaae52c | 2021-03-11 16:17:50 -0800 | [diff] [blame] | 1 | //===-- Implementation of mktime function ---------------------------------===// |
| 2 | // |
| 3 | // Part of the LLVM Project, under the Apache License v2.0 with LLVM Exceptions. |
| 4 | // See https://llvm.org/LICENSE.txt for license information. |
| 5 | // SPDX-License-Identifier: Apache-2.0 WITH LLVM-exception |
| 6 | // |
| 7 | //===----------------------------------------------------------------------===// |
| 8 | |
| 9 | #include "src/time/time_utils.h" |
| 10 | #include "src/__support/common.h" |
| 11 | |
| 12 | #include <limits.h> |
| 13 | |
| 14 | namespace __llvm_libc { |
| 15 | namespace time_utils { |
| 16 | |
| 17 | using __llvm_libc::time_utils::TimeConstants; |
| 18 | |
| 19 | static int64_t computeRemainingYears(int64_t daysPerYears, |
| 20 | int64_t quotientYears, |
| 21 | int64_t *remainingDays) { |
| 22 | int64_t years = *remainingDays / daysPerYears; |
| 23 | if (years == quotientYears) |
| 24 | years--; |
| 25 | *remainingDays -= years * daysPerYears; |
| 26 | return years; |
| 27 | } |
| 28 | |
| 29 | // First, divide "total_seconds" by the number of seconds in a day to get the |
| 30 | // number of days since Jan 1 1970. The remainder will be used to calculate the |
| 31 | // number of Hours, Minutes and Seconds. |
| 32 | // |
| 33 | // Then, adjust that number of days by a constant to be the number of days |
| 34 | // since Mar 1 2000. Year 2000 is a multiple of 400, the leap year cycle. This |
| 35 | // makes it easier to count how many leap years have passed using division. |
| 36 | // |
| 37 | // While calculating numbers of years in the days, the following algorithm |
| 38 | // subdivides the days into the number of 400 years, the number of 100 years and |
| 39 | // the number of 4 years. These numbers of cycle years are used in calculating |
| 40 | // leap day. This is similar to the algorithm used in getNumOfLeapYearsBefore() |
| 41 | // and isLeapYear(). Then compute the total number of years in days from these |
| 42 | // subdivided units. |
| 43 | // |
| 44 | // Compute the number of months from the remaining days. Finally, adjust years |
| 45 | // to be 1900 and months to be from January. |
| 46 | int64_t UpdateFromSeconds(int64_t total_seconds, struct tm *tm) { |
| 47 | // Days in month starting from March in the year 2000. |
| 48 | static const char daysInMonth[] = {31 /* Mar */, 30, 31, 30, 31, 31, |
| 49 | 30, 31, 30, 31, 31, 29}; |
| 50 | |
| 51 | if (sizeof(time_t) == 4) { |
| 52 | if (total_seconds < 0x80000000) |
| 53 | return time_utils::OutOfRange(); |
| 54 | if (total_seconds > 0x7FFFFFFF) |
| 55 | return time_utils::OutOfRange(); |
| 56 | } else { |
| 57 | if (total_seconds < |
| 58 | INT_MIN * static_cast<int64_t>( |
| 59 | TimeConstants::NumberOfSecondsInLeapYear) || |
| 60 | total_seconds > INT_MAX * static_cast<int64_t>( |
| 61 | TimeConstants::NumberOfSecondsInLeapYear)) |
| 62 | return time_utils::OutOfRange(); |
| 63 | } |
| 64 | |
| 65 | int64_t seconds = total_seconds - TimeConstants::SecondsUntil2000MarchFirst; |
| 66 | int64_t days = seconds / TimeConstants::SecondsPerDay; |
| 67 | int64_t remainingSeconds = seconds % TimeConstants::SecondsPerDay; |
| 68 | if (remainingSeconds < 0) { |
| 69 | remainingSeconds += TimeConstants::SecondsPerDay; |
| 70 | days--; |
| 71 | } |
| 72 | |
| 73 | int64_t wday = (TimeConstants::WeekDayOf2000MarchFirst + days) % |
| 74 | TimeConstants::DaysPerWeek; |
| 75 | if (wday < 0) |
| 76 | wday += TimeConstants::DaysPerWeek; |
| 77 | |
| 78 | // Compute the number of 400 year cycles. |
| 79 | int64_t numOfFourHundredYearCycles = days / TimeConstants::DaysPer400Years; |
| 80 | int64_t remainingDays = days % TimeConstants::DaysPer400Years; |
| 81 | if (remainingDays < 0) { |
| 82 | remainingDays += TimeConstants::DaysPer400Years; |
| 83 | numOfFourHundredYearCycles--; |
| 84 | } |
| 85 | |
| 86 | // The reminder number of years after computing number of |
| 87 | // "four hundred year cycles" will be 4 hundred year cycles or less in 400 |
| 88 | // years. |
| 89 | int64_t numOfHundredYearCycles = |
| 90 | computeRemainingYears(TimeConstants::DaysPer100Years, 4, &remainingDays); |
| 91 | |
| 92 | // The reminder number of years after computing number of |
| 93 | // "hundred year cycles" will be 25 four year cycles or less in 100 years. |
| 94 | int64_t numOfFourYearCycles = |
| 95 | computeRemainingYears(TimeConstants::DaysPer4Years, 25, &remainingDays); |
| 96 | |
| 97 | // The reminder number of years after computing number of "four year cycles" |
| 98 | // will be 4 one year cycles or less in 4 years. |
| 99 | int64_t remainingYears = computeRemainingYears( |
| 100 | TimeConstants::DaysPerNonLeapYear, 4, &remainingDays); |
| 101 | |
| 102 | // Calculate number of years from year 2000. |
| 103 | int64_t years = remainingYears + 4 * numOfFourYearCycles + |
| 104 | 100 * numOfHundredYearCycles + |
| 105 | 400LL * numOfFourHundredYearCycles; |
| 106 | |
| 107 | int leapDay = |
| 108 | !remainingYears && (numOfFourYearCycles || !numOfHundredYearCycles); |
| 109 | |
| 110 | int64_t yday = remainingDays + 31 + 28 + leapDay; |
| 111 | if (yday >= TimeConstants::DaysPerNonLeapYear + leapDay) |
| 112 | yday -= TimeConstants::DaysPerNonLeapYear + leapDay; |
| 113 | |
| 114 | int64_t months = 0; |
| 115 | while (daysInMonth[months] <= remainingDays) { |
| 116 | remainingDays -= daysInMonth[months]; |
| 117 | months++; |
| 118 | } |
| 119 | |
| 120 | if (months >= TimeConstants::MonthsPerYear - 2) { |
| 121 | months -= TimeConstants::MonthsPerYear; |
| 122 | years++; |
| 123 | } |
| 124 | |
| 125 | if (years > INT_MAX || years < INT_MIN) |
| 126 | return time_utils::OutOfRange(); |
| 127 | |
| 128 | // All the data (years, month and remaining days) was calculated from |
| 129 | // March, 2000. Thus adjust the data to be from January, 1900. |
| 130 | tm->tm_year = years + 2000 - TimeConstants::TimeYearBase; |
| 131 | tm->tm_mon = months + 2; |
| 132 | tm->tm_mday = remainingDays + 1; |
| 133 | tm->tm_wday = wday; |
| 134 | tm->tm_yday = yday; |
| 135 | |
| 136 | tm->tm_hour = remainingSeconds / TimeConstants::SecondsPerHour; |
| 137 | tm->tm_min = remainingSeconds / TimeConstants::SecondsPerMin % |
| 138 | TimeConstants::SecondsPerMin; |
| 139 | tm->tm_sec = remainingSeconds % TimeConstants::SecondsPerMin; |
| 140 | // TODO(rtenneti): Need to handle timezone and update of tm_isdst. |
| 141 | tm->tm_isdst = 0; |
| 142 | |
| 143 | return 0; |
| 144 | } |
| 145 | |
| 146 | } // namespace time_utils |
| 147 | } // namespace __llvm_libc |