| //===- llvm/Support/SuffixTree.cpp - Implement Suffix Tree ------*- C++ -*-===// | |
| // | |
| // Part of the LLVM Project, under the Apache License v2.0 with LLVM Exceptions. | |
| // See https://llvm.org/LICENSE.txt for license information. | |
| // SPDX-License-Identifier: Apache-2.0 WITH LLVM-exception | |
| // | |
| //===----------------------------------------------------------------------===// | |
| // | |
| // This file implements the Suffix Tree class. | |
| // | |
| //===----------------------------------------------------------------------===// | |
| #include "llvm/Support/SuffixTree.h" | |
| #include "llvm/Support/Allocator.h" | |
| #include "llvm/Support/Casting.h" | |
| #include "llvm/Support/SuffixTreeNode.h" | |
| using namespace llvm; | |
| /// \returns the number of elements in the substring associated with \p N. | |
| static size_t numElementsInSubstring(const SuffixTreeNode *N) { | |
| assert(N && "Got a null node?"); | |
| if (auto *Internal = dyn_cast<SuffixTreeInternalNode>(N)) | |
| if (Internal->isRoot()) | |
| return 0; | |
| return N->getEndIdx() - N->getStartIdx() + 1; | |
| } | |
| SuffixTree::SuffixTree(const ArrayRef<unsigned> &Str, | |
| bool OutlinerLeafDescendants) | |
| : Str(Str), OutlinerLeafDescendants(OutlinerLeafDescendants) { | |
| Root = insertRoot(); | |
| Active.Node = Root; | |
| // Keep track of the number of suffixes we have to add of the current | |
| // prefix. | |
| unsigned SuffixesToAdd = 0; | |
| // Construct the suffix tree iteratively on each prefix of the string. | |
| // PfxEndIdx is the end index of the current prefix. | |
| // End is one past the last element in the string. | |
| for (unsigned PfxEndIdx = 0, End = Str.size(); PfxEndIdx < End; PfxEndIdx++) { | |
| SuffixesToAdd++; | |
| LeafEndIdx = PfxEndIdx; // Extend each of the leaves. | |
| SuffixesToAdd = extend(PfxEndIdx, SuffixesToAdd); | |
| } | |
| // Set the suffix indices of each leaf. | |
| assert(Root && "Root node can't be nullptr!"); | |
| setSuffixIndices(); | |
| // Collect all leaf nodes of the suffix tree. And for each internal node, | |
| // record the range of leaf nodes that are descendants of it. | |
| if (OutlinerLeafDescendants) | |
| setLeafNodes(); | |
| } | |
| SuffixTreeNode *SuffixTree::insertLeaf(SuffixTreeInternalNode &Parent, | |
| unsigned StartIdx, unsigned Edge) { | |
| assert(StartIdx <= LeafEndIdx && "String can't start after it ends!"); | |
| auto *N = new (LeafNodeAllocator.Allocate()) | |
| SuffixTreeLeafNode(StartIdx, &LeafEndIdx); | |
| Parent.Children[Edge] = N; | |
| return N; | |
| } | |
| SuffixTreeInternalNode * | |
| SuffixTree::insertInternalNode(SuffixTreeInternalNode *Parent, | |
| unsigned StartIdx, unsigned EndIdx, | |
| unsigned Edge) { | |
| assert(StartIdx <= EndIdx && "String can't start after it ends!"); | |
| assert(!(!Parent && StartIdx != SuffixTreeNode::EmptyIdx) && | |
| "Non-root internal nodes must have parents!"); | |
| auto *N = new (InternalNodeAllocator.Allocate()) | |
| SuffixTreeInternalNode(StartIdx, EndIdx, Root); | |
| if (Parent) | |
| Parent->Children[Edge] = N; | |
| return N; | |
| } | |
| SuffixTreeInternalNode *SuffixTree::insertRoot() { | |
| return insertInternalNode(/*Parent = */ nullptr, SuffixTreeNode::EmptyIdx, | |
| SuffixTreeNode::EmptyIdx, /*Edge = */ 0); | |
| } | |
| void SuffixTree::setSuffixIndices() { | |
| // List of nodes we need to visit along with the current length of the | |
| // string. | |
| SmallVector<std::pair<SuffixTreeNode *, unsigned>> ToVisit; | |
| // Current node being visited. | |
| SuffixTreeNode *CurrNode = Root; | |
| // Sum of the lengths of the nodes down the path to the current one. | |
| unsigned CurrNodeLen = 0; | |
| ToVisit.push_back({CurrNode, CurrNodeLen}); | |
| while (!ToVisit.empty()) { | |
| std::tie(CurrNode, CurrNodeLen) = ToVisit.pop_back_val(); | |
| // Length of the current node from the root down to here. | |
| CurrNode->setConcatLen(CurrNodeLen); | |
| if (auto *InternalNode = dyn_cast<SuffixTreeInternalNode>(CurrNode)) | |
| for (auto &ChildPair : InternalNode->Children) { | |
| assert(ChildPair.second && "Node had a null child!"); | |
| ToVisit.push_back( | |
| {ChildPair.second, | |
| CurrNodeLen + numElementsInSubstring(ChildPair.second)}); | |
| } | |
| // No children, so we are at the end of the string. | |
| if (auto *LeafNode = dyn_cast<SuffixTreeLeafNode>(CurrNode)) | |
| LeafNode->setSuffixIdx(Str.size() - CurrNodeLen); | |
| } | |
| } | |
| void SuffixTree::setLeafNodes() { | |
| // A stack that keeps track of nodes to visit for post-order DFS traversal. | |
| SmallVector<SuffixTreeNode *> ToVisit; | |
| ToVisit.push_back(Root); | |
| // This keeps track of the index of the next leaf node to be added to | |
| // the LeafNodes vector of the suffix tree. | |
| unsigned LeafCounter = 0; | |
| // This keeps track of nodes whose children have been added to the stack. | |
| // The value is a pair, representing a node's first and last children. | |
| DenseMap<SuffixTreeInternalNode *, | |
| std::pair<SuffixTreeNode *, SuffixTreeNode *>> | |
| ChildrenMap; | |
| // Traverse the tree in post-order. | |
| while (!ToVisit.empty()) { | |
| SuffixTreeNode *CurrNode = ToVisit.pop_back_val(); | |
| if (auto *CurrInternalNode = dyn_cast<SuffixTreeInternalNode>(CurrNode)) { | |
| // The current node is an internal node. | |
| auto I = ChildrenMap.find(CurrInternalNode); | |
| if (I == ChildrenMap.end()) { | |
| // This is the first time we visit this node. | |
| // Its children have not been added to the stack yet. | |
| // We add current node back, and add its children to the stack. | |
| // We keep track of the first and last children of the current node. | |
| auto J = CurrInternalNode->Children.begin(); | |
| if (J != CurrInternalNode->Children.end()) { | |
| ToVisit.push_back(CurrNode); | |
| SuffixTreeNode *FirstChild = J->second; | |
| SuffixTreeNode *LastChild = nullptr; | |
| for (; J != CurrInternalNode->Children.end(); ++J) { | |
| LastChild = J->second; | |
| ToVisit.push_back(LastChild); | |
| } | |
| ChildrenMap[CurrInternalNode] = {FirstChild, LastChild}; | |
| } | |
| } else { | |
| // This is the second time we visit this node. | |
| // All of its children have already been processed. | |
| // Now, we can set its LeftLeafIdx and RightLeafIdx; | |
| auto [FirstChild, LastChild] = I->second; | |
| // Get the first child to use its RightLeafIdx. | |
| // The first child is the first one added to the stack, so it is | |
| // the last one to be processed. Hence, the leaf descendants | |
| // of the first child are assigned the largest index numbers. | |
| CurrNode->setRightLeafIdx(FirstChild->getRightLeafIdx()); | |
| // Get the last child to use its LeftLeafIdx. | |
| CurrNode->setLeftLeafIdx(LastChild->getLeftLeafIdx()); | |
| assert(CurrNode->getLeftLeafIdx() <= CurrNode->getRightLeafIdx() && | |
| "LeftLeafIdx should not be larger than RightLeafIdx"); | |
| } | |
| } else { | |
| // The current node is a leaf node. | |
| // We can simply set its LeftLeafIdx and RightLeafIdx. | |
| CurrNode->setLeftLeafIdx(LeafCounter); | |
| CurrNode->setRightLeafIdx(LeafCounter); | |
| ++LeafCounter; | |
| auto *CurrLeafNode = cast<SuffixTreeLeafNode>(CurrNode); | |
| LeafNodes.push_back(CurrLeafNode); | |
| } | |
| } | |
| } | |
| unsigned SuffixTree::extend(unsigned EndIdx, unsigned SuffixesToAdd) { | |
| SuffixTreeInternalNode *NeedsLink = nullptr; | |
| while (SuffixesToAdd > 0) { | |
| // Are we waiting to add anything other than just the last character? | |
| if (Active.Len == 0) { | |
| // If not, then say the active index is the end index. | |
| Active.Idx = EndIdx; | |
| } | |
| assert(Active.Idx <= EndIdx && "Start index can't be after end index!"); | |
| // The first character in the current substring we're looking at. | |
| unsigned FirstChar = Str[Active.Idx]; | |
| // Have we inserted anything starting with FirstChar at the current node? | |
| if (auto It = Active.Node->Children.find(FirstChar); | |
| It == Active.Node->Children.end()) { | |
| // If not, then we can just insert a leaf and move to the next step. | |
| insertLeaf(*Active.Node, EndIdx, FirstChar); | |
| // The active node is an internal node, and we visited it, so it must | |
| // need a link if it doesn't have one. | |
| if (NeedsLink) { | |
| NeedsLink->setLink(Active.Node); | |
| NeedsLink = nullptr; | |
| } | |
| } else { | |
| // There's a match with FirstChar, so look for the point in the tree to | |
| // insert a new node. | |
| SuffixTreeNode *NextNode = It->second; | |
| unsigned SubstringLen = numElementsInSubstring(NextNode); | |
| // Is the current suffix we're trying to insert longer than the size of | |
| // the child we want to move to? | |
| if (Active.Len >= SubstringLen) { | |
| // If yes, then consume the characters we've seen and move to the next | |
| // node. | |
| assert(isa<SuffixTreeInternalNode>(NextNode) && | |
| "Expected an internal node?"); | |
| Active.Idx += SubstringLen; | |
| Active.Len -= SubstringLen; | |
| Active.Node = cast<SuffixTreeInternalNode>(NextNode); | |
| continue; | |
| } | |
| // Otherwise, the suffix we're trying to insert must be contained in the | |
| // next node we want to move to. | |
| unsigned LastChar = Str[EndIdx]; | |
| // Is the string we're trying to insert a substring of the next node? | |
| if (Str[NextNode->getStartIdx() + Active.Len] == LastChar) { | |
| // If yes, then we're done for this step. Remember our insertion point | |
| // and move to the next end index. At this point, we have an implicit | |
| // suffix tree. | |
| if (NeedsLink && !Active.Node->isRoot()) { | |
| NeedsLink->setLink(Active.Node); | |
| NeedsLink = nullptr; | |
| } | |
| Active.Len++; | |
| break; | |
| } | |
| // The string we're trying to insert isn't a substring of the next node, | |
| // but matches up to a point. Split the node. | |
| // | |
| // For example, say we ended our search at a node n and we're trying to | |
| // insert ABD. Then we'll create a new node s for AB, reduce n to just | |
| // representing C, and insert a new leaf node l to represent d. This | |
| // allows us to ensure that if n was a leaf, it remains a leaf. | |
| // | |
| // | ABC ---split---> | AB | |
| // n s | |
| // C / \ D | |
| // n l | |
| // The node s from the diagram | |
| SuffixTreeInternalNode *SplitNode = insertInternalNode( | |
| Active.Node, NextNode->getStartIdx(), | |
| NextNode->getStartIdx() + Active.Len - 1, FirstChar); | |
| // Insert the new node representing the new substring into the tree as | |
| // a child of the split node. This is the node l from the diagram. | |
| insertLeaf(*SplitNode, EndIdx, LastChar); | |
| // Make the old node a child of the split node and update its start | |
| // index. This is the node n from the diagram. | |
| NextNode->incrementStartIdx(Active.Len); | |
| SplitNode->Children[Str[NextNode->getStartIdx()]] = NextNode; | |
| // SplitNode is an internal node, update the suffix link. | |
| if (NeedsLink) | |
| NeedsLink->setLink(SplitNode); | |
| NeedsLink = SplitNode; | |
| } | |
| // We've added something new to the tree, so there's one less suffix to | |
| // add. | |
| SuffixesToAdd--; | |
| if (Active.Node->isRoot()) { | |
| if (Active.Len > 0) { | |
| Active.Len--; | |
| Active.Idx = EndIdx - SuffixesToAdd + 1; | |
| } | |
| } else { | |
| // Start the next phase at the next smallest suffix. | |
| Active.Node = Active.Node->getLink(); | |
| } | |
| } | |
| return SuffixesToAdd; | |
| } | |
| void SuffixTree::RepeatedSubstringIterator::advance() { | |
| // Clear the current state. If we're at the end of the range, then this | |
| // is the state we want to be in. | |
| RS = RepeatedSubstring(); | |
| N = nullptr; | |
| // Each leaf node represents a repeat of a string. | |
| SmallVector<unsigned> RepeatedSubstringStarts; | |
| // Continue visiting nodes until we find one which repeats more than once. | |
| while (!InternalNodesToVisit.empty()) { | |
| RepeatedSubstringStarts.clear(); | |
| auto *Curr = InternalNodesToVisit.pop_back_val(); | |
| // Keep track of the length of the string associated with the node. If | |
| // it's too short, we'll quit. | |
| unsigned Length = Curr->getConcatLen(); | |
| // Iterate over each child, saving internal nodes for visiting. | |
| // Internal nodes represent individual strings, which may repeat. | |
| for (auto &ChildPair : Curr->Children) | |
| // Save all of this node's children for processing. | |
| if (auto *InternalChild = | |
| dyn_cast<SuffixTreeInternalNode>(ChildPair.second)) | |
| InternalNodesToVisit.push_back(InternalChild); | |
| // If length of repeated substring is below threshold, then skip it. | |
| if (Length < MinLength) | |
| continue; | |
| // The root never represents a repeated substring. If we're looking at | |
| // that, then skip it. | |
| if (Curr->isRoot()) | |
| continue; | |
| // Collect leaf children or leaf descendants by OutlinerLeafDescendants. | |
| if (OutlinerLeafDescendants) { | |
| for (unsigned I = Curr->getLeftLeafIdx(); I <= Curr->getRightLeafIdx(); | |
| ++I) | |
| RepeatedSubstringStarts.push_back(LeafNodes[I]->getSuffixIdx()); | |
| } else { | |
| for (auto &ChildPair : Curr->Children) | |
| if (auto *Leaf = dyn_cast<SuffixTreeLeafNode>(ChildPair.second)) | |
| RepeatedSubstringStarts.push_back(Leaf->getSuffixIdx()); | |
| } | |
| // Do we have any repeated substrings? | |
| if (RepeatedSubstringStarts.size() < 2) | |
| continue; | |
| // Yes. Update the state to reflect this, and then bail out. | |
| N = Curr; | |
| RS.Length = Length; | |
| llvm::append_range(RS.StartIndices, RepeatedSubstringStarts); | |
| break; | |
| } | |
| // At this point, either NewRS is an empty RepeatedSubstring, or it was | |
| // set in the above loop. Similarly, N is either nullptr, or the node | |
| // associated with NewRS. | |
| } |