| // RUN: %clang_analyze_cc1 %s \ | |
| // RUN: -analyzer-checker=core \ | |
| // RUN: -analyzer-checker=debug.ExprInspection \ | |
| // RUN: 2>&1 | FileCheck %s | |
| // In this test we check whether the solver's symbol simplification mechanism | |
| // is capable of reaching a fixpoint. This should be done after TWO iterations. | |
| void clang_analyzer_printState(); | |
| void test(int a, int b, int c, int d) { | |
| if (a + b + c != d) | |
| return; | |
| if (c + b != 0) | |
| return; | |
| clang_analyzer_printState(); | |
| // CHECK: "constraints": [ | |
| // CHECK-NEXT: { "symbol": "(((reg_$0<int a>) + (reg_$2<int b>)) + (reg_$5<int c>)) != (reg_$8<int d>)", "range": "{ [0, 0] }" }, | |
| // CHECK-NEXT: { "symbol": "(reg_$5<int c>) + (reg_$2<int b>)", "range": "{ [0, 0] }" } | |
| // CHECK-NEXT: ], | |
| // CHECK-NEXT: "equivalence_classes": [ | |
| // CHECK-NEXT: [ "((reg_$0<int a>) + (reg_$2<int b>)) + (reg_$5<int c>)", "reg_$8<int d>" ] | |
| // CHECK-NEXT: ], | |
| // CHECK-NEXT: "disequality_info": null, | |
| // Simplification starts here. | |
| if (b != 0) | |
| return; | |
| clang_analyzer_printState(); | |
| // CHECK: "constraints": [ | |
| // CHECK-NEXT: { "symbol": "(reg_$0<int a>) != (reg_$8<int d>)", "range": "{ [0, 0] }" }, | |
| // CHECK-NEXT: { "symbol": "reg_$2<int b>", "range": "{ [0, 0] }" }, | |
| // CHECK-NEXT: { "symbol": "reg_$5<int c>", "range": "{ [0, 0] }" } | |
| // CHECK-NEXT: ], | |
| // CHECK-NEXT: "equivalence_classes": [ | |
| // CHECK-NEXT: [ "(reg_$0<int a>) != (reg_$8<int d>)" ], | |
| // CHECK-NEXT: [ "reg_$0<int a>", "reg_$8<int d>" ], | |
| // CHECK-NEXT: [ "reg_$5<int c>" ] | |
| // CHECK-NEXT: ], | |
| // CHECK-NEXT: "disequality_info": null, | |
| // Keep the symbols and the constraints! alive. | |
| (void)(a * b * c * d); | |
| return; | |
| } |