; This test makes sure that these instructions are properly eliminated.
;

; RUN: opt < %s -instcombine -S | not grep xor

define i32 @test1(i32 %A) {
        %B = xor i32 %A, -1             ; <i32> [#uses=1]
        %C = xor i32 %B, -1             ; <i32> [#uses=1]
        ret i32 %C
}

define i1 @test2(i32 %A, i32 %B) {
        ; Can change into setge
        %cond = icmp sle i32 %A, %B             ; <i1> [#uses=1]
        %Ret = xor i1 %cond, true               ; <i1> [#uses=1]
        ret i1 %Ret
}

; Test that demorgans law can be instcombined
define i32 @test3(i32 %A, i32 %B) {
        %a = xor i32 %A, -1             ; <i32> [#uses=1]
        %b = xor i32 %B, -1             ; <i32> [#uses=1]
        %c = and i32 %a, %b             ; <i32> [#uses=1]
        %d = xor i32 %c, -1             ; <i32> [#uses=1]
        ret i32 %d
}

; Test that demorgens law can work with constants
define i32 @test4(i32 %A, i32 %B) {
        %a = xor i32 %A, -1             ; <i32> [#uses=1]
        %c = and i32 %a, 5              ; <i32> [#uses=1]
        %d = xor i32 %c, -1             ; <i32> [#uses=1]
        ret i32 %d
}

; test the mirror of demorgans law...
define i32 @test5(i32 %A, i32 %B) {
        %a = xor i32 %A, -1             ; <i32> [#uses=1]
        %b = xor i32 %B, -1             ; <i32> [#uses=1]
        %c = or i32 %a, %b              ; <i32> [#uses=1]
        %d = xor i32 %c, -1             ; <i32> [#uses=1]
        ret i32 %d
}

; PR2298
define i8 @test6(i32 %a, i32 %b) zeroext nounwind  {
entry:
	%tmp1not = xor i32 %a, -1		; <i32> [#uses=1]
	%tmp2not = xor i32 %b, -1		; <i32> [#uses=1]
	%tmp3 = icmp slt i32 %tmp1not, %tmp2not		; <i1> [#uses=1]
	%retval67 = zext i1 %tmp3 to i8		; <i8> [#uses=1]
	ret i8 %retval67
}