| commit | 4c71375f07ad5e79f2063cef4cc2deb8ef015731 | [log] [tgz] |
|---|---|---|
| author | Louis Dionne <ldionne@apple.com> | Thu Aug 27 13:09:23 2020 -0400 |
| committer | Copybara-Service <copybara-worker@google.com> | Thu Aug 27 20:42:31 2020 -0700 |
| tree | d0d61846b0afec53bb8456b38a86fdb6e00a4511 | |
| parent | 30a1f6bfd24e0d79d9f3d045ca5a13382f11a6b6 [diff] |
[libc++][NFC] Define functor's call operator inline This fixes a mismatched visibility attribute on the call operator in addition to making the code clearer. Given this is a simple lambda in essence, the intent has always been to give it inline visibility. GitOrigin-RevId: 21a1a263a6d9c0c44ef8eb0744786e2aa5d59e53